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C++ # is not followed by a macro parameter

WebOct 28, 2024 · Argument substitution expansion only occurs if the parameter in the macro corresponds to one in the replacement list (and that parameter isn't stringified with the # … WebMar 25, 2006 · C++ and C). By definition a macro (the part after the #define) ends on the same line. This can be partially ameliorated by the use of continuation lines (where the …

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WebMar 1, 2012 · You can use a variadic macro and then pass the string format and the function parameters to it. The macro won't be exactly the same for every function (as … WebJun 25, 2016 · To use proper C99 variadic macros, you should be compiling with a C compiler that supports C99 (like gcc), not a C++ compiler, since C++ doesn't have standard variadic macros. – Chris Lutz Mar 25, 2009 at 2:13 Well, I assumed C++ is a super set of C in this regard .. – hasen Mar 25, 2009 at 3:46 cannabis use meme cheech and chong employment https://adremeval.com

c++ - Macro to Get function name and parameter values from …

WebNov 19, 2024 · There are 2 problems with your macro definition: It uses incorrect syntax The name of a variable may be passed as a; in this case you cannot simply put the variable next to 2 string literals to do a concatenation. The latter problem can be solved by using a string and the + operator or simply using multiple printf s. WebMay 30, 2012 · do not enclose arguments of macro in parentheses in the macro body, so if those arguments are expressions, operators with different precedences in those … WebSep 26, 2024 · 1. I'm trying to write a macro that generates code for an object pool for any given class of objects in C. I keep getting error: '#' is not followed by a macro … cannabis use in united states

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C++ # is not followed by a macro parameter

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Web2 days ago · I want to call the show.py in my Qt project. The p_stdout should be hello, but I just get an empty string "", the exit code is 1, and the exit status is QProcess::NormalExit. This is my WebJun 9, 2024 · You can define a variadic macro in C++ like: #define FOO (x, ...) bar (x, __VA_ARGS__) But calling FOO as FOO (1) results in the macro expansion bar (1,) which is obviously a syntactical error and won't compile. Therefore GCC includes a GNU extension: #define FOO (x, ...) bar (x, ##__VA_ARGS__)

C++ # is not followed by a macro parameter

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WebNov 6, 2008 · C and C++ languages explicitly prohibit forming preprocessor directives as the result of macro expansion. This means that you can't include a preprocessor directive … WebAug 17, 2011 · This question describes a way to suppress the unused parameter warning by writing a macro inside the function code: Universally compiler independent way of implementing an UNUSED macro in C/C++ But I'm interested in a macro that can be used in the function signature: void callback (int UNUSED (some_useless_stuff)) {}

WebNov 20, 2024 · You can fix this with an extra "helper" macro: #define MAX_NAME_LEN 15 #define STRINGIFY (s) \ #s #define PRINT_CELL (x) \ printf (" %" STRINGIFY … WebJun 4, 2016 · A better way to avoid the warning is to use a dummy macro that expands to nothing, e.g. #define NOARG then you can use MY_MACRO (NOARG, bar, baz). – Rufflewind Jun 4, 2016 at 12:43 Add a comment Your Answer By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy Not the …

WebSep 25, 2015 · It's a pity that the defined operator is available only in the context of #if and #ifelse, but not for macro expansions. As it stands, I agree with rici about the solutions … WebJan 25, 2024 · No, this is not possible. During translation, all preprocessing directives ( #define, #include, etc.) are executed before any macro expansion occurs, so if a macro expands into a preprocessing directive, it won't be interpreted as such - it will be interpreted as (invalid) source code. Share Improve this answer Follow answered Jan 24, 2024 at …

Webpasses two arguments to macro: array[x = yand x + 1]. If you want to supply array[x = y, x + 1]as an argument, you can write it as array[(x = y, x + 1)], which is equivalent C code. All …

WebMar 2, 2016 · Since you added the C++ tag not using macros is a valid answer. If you just want to talk about the pre-processor just tag it as pre-processor and not C++ – Martin York Nov 22, 2010 at 23:20 15 @Martin: The preprocessor is as much a part of C++ as the STL is; should questions about the STL be tagged [stl] and not [c++] too? fix leaky shower valve stemWebJan 4, 2016 · Such macros are called by writing. macro_identifier () in the subsequent source code. The syntax is identical to that of a … fix leaky shower faucet deltaWebMar 31, 2024 · How to redefine c++ macro with reduced parameters? Ask Question Asked 7 days ago Modified 5 days ago Viewed 54 times 0 I have following macros in an existing project, #define TRACE1 (attr,str,...) REL_LOG (attr, str, ##_VA_ARGS__) #define TRACE2 (str,...) REL_LOG (str, ##_VA_ARGS__) And they have been used like, cannabis use linked to schizophreniaWebApr 4, 2024 · (since C++11) Otherwise, the behavior is undefined. # and ## operators In function-like macros, a # operator before an identifier in the replacement-list runs the … fix leaky shower drainWebJun 22, 2011 · As JAB pointed, macros are different than functions, they do not require the type of arguments #define TRACERPTR (pReporter, eComponent, eLevel, sFormat, formatArgs...) \ if (pReporter != NULL) { pReporter->trace (eComponent, eLevel, sFormat, ##formatArgs); } Share Improve this answer Follow answered Jun 20, 2011 at 19:27 … cannabis use mental healthWebApr 13, 2024 · Then, we initialize each thread giving it the function to execute ** multiply_threading ** that has the following signature: ```c void multiply_threading(Matrix& result, const int thread_number, const Matrix& m1, const Matrix& m2); ``` The first parameter is the output matrix, The second parameter is the thread number (later on … fix leaky shut off valveWebJun 20, 2015 · You could get a clear compilation error if you converted the selected argument which is supposed to be a MACRO name to string using # (the pound sign) and compared it's first n characters with the expected prefix and if there is no match, printed an informative error. – AturSams Jan 7, 2014 at 16:01 1 cannabis use schizophrenia