In an ap a 1 an 20 sn 399

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WebSolution Given: First term ( a) = a 1 = 1 n th term = a n = 20 Sum of n terms = S n = 399 Now, a n = a + n - 1 d ⇒ 20 = 1 + n - 1 d ⇒ n - 1 d = 20 - 1 ⇒ n - 1 d = 19... 1 S n = n 2 2 a + n - 1 d ⇒ 399 = n 2 2 1 + 19 From 1 ⇒ 399 = n 2 21 ⇒ 798 = 21 n ⇒ n = 798 21 ⇒ n = 38 Hence, the value of n is 38. Suggest Corrections 0 Similar questions Q. WebFeb 27, 2012 · In an AP if a=1, an= 20 and sn =399 then n is a) 13 b) 38 c) 21 d)19 - Maths - Arithmetic Progressions

In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to …

WebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? has been provided alongside types of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? theory, EduRev gives you an ample number of questions to … WebIf in an AP a = 1, t n = 20 and Sn = 399 then n is (a) 19 (b) 21 (c) 38 (d) 42 Report 497 Share Follow Answer peter Reputation: 2.6K University of Lagos, Nigeria 30 July 2024 Comments 1 answer (s) ADVERTISEMENT - CONTINUE BELOW judziy Reputation: 3.0K University of Benin, Nigeria 30 July 2024 1 little buddy heater propane tank adapter

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WebIf an A.P. has a = 1, t n = 20 and s n = 399, then value of n is : A. 20 B. 32 C. 38 D. 40 Answer: Option C Solution (By Examveda Team) S n = 1 2 ( a + l) × n ⇒ 399 = ( 1 + 20) × n 2 ⇒ 399 × 2 = 21 × n ⇒ n = 399 × 2 21 ⇒ n = 19 × 2 ⇒ n = 38 Join The Discussion Related Questions on Progressions How many terms are there in 20, 25, 30 . . . . . . 140? WebIn an AP, if a = 1, an = 20 and Sn = 399, then n is equal to (a) 19 (b) 21 (c) 38 (d) 42 Solution: Question 18: The sum of first five multiples of 3 is (a) 45 (b) 55 (c) 65 (d) 75 Solution: (a) The first five multiples of 3 are 3, 6, 9,12 and 15. Here, first term, a = 3, common difference, d = 6-3 = 3 and number of terms, n = 5 WebFeb 11, 2013 · if an ap a=1 ,an=20,sn= 399 then n is Asked by anish mishra 11 Feb, 2013, 02:45: PM Expert Answer Sn=399 => n/2 (a + an) = 399 => n/2 ( 1 + 20) = 399 =>n/2 (21) = 399 => n = 399 X 2/21 => n= 38 Answered by 11 Feb, 2013, 05:49: PM Application Videos This video explains the concept of Arithmetic Progression, Solving Linear E... little buddy heater filter

In an A.P., if a = 1, an = 20 and sn = 399 then n is - Toppr

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WebIf in an AP a = 1, t n = 20 and Sn = 399 then n is (a) 19 (b) 21 (c) 38 (d) 42 Report 497 Share Follow Answer peter Reputation: 2.6K University of Lagos, Nigeria 30 July 2024 … WebDec 17, 2024 · In an A.P., if an = 1, a = 20 and Sn = 399, then n = ……………… A) 19 B) 42 C) 28 D) 38 arithmetic progression class-10 Share It On 2 Answers +1 vote answered Mar 22 by … little buddy heater modificationsWebIn an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42. 2Pi classes. 36.7K subscribers. little buddy heater reviews

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In an ap a 1 an 20 sn 399

In an A.P 1^st term is 1 and the last term is 20 . The sum of all …

WebFeb 26, 2016 · Find an answer to your question In an AP, if a=1,an=20 and Sn= 399, then n=? yoyphcrazyp yoyphcrazyp 26.02.2016 Math Secondary School answered In an AP, if a=1,an=20 and Sn= 399, then n=? 2 See answers Cn u make the question little clear? Advertisement Advertisement Shree99 Shree99 WebQuestion If an AP has a = 1, a n = 20 and S n = 399, then find the value of n. Solution Compute the value of n: Formulae: The n th term of an AP is a n = a + n - 1 d and the sum of n terms of a series in an AP is S n = n 2 2 a + ( n - 1) d. Substitute a = 1, a n = 20 in the n th term of an AP formula.

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Web⇒ n = 2 1 7 9 8 = 3 8 So, the no. of terms in the given A.P. for which the sum = 3 9 9 is 38. Final Step: Hence, the no. of term in the given A.P. for which the sum is 399 is 38. WebIn an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 Home Get Answers to all your Questions Home NCERT In an AP if a = 1, an = 20 and Sn = 399, then n is (A) 19 (B) 21 (C) 38 (D) 42 #Arithmetic Progressions #NCERT #Maths #Exemplar Maths for Class 10 #1.3 #5.2 #5.3 #5.4 #5.1 #9.2 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0 1.0

WebAug 25, 2024 · In an AP, if a = 1, an = 20 and Sn = 399, then n is equal to A. 19 B. 21 C. 38 D. 42. ← Prev Question Next Question →. 0 votes. 17.2k views. asked Aug 25, 2024 in … WebIn an AP if a=1, an =20 and Sn =399, then n is Q. If an AP has a=1, tn=20 and Sn=399, then the value of n is Q. In an AP, if d = - 4 , n = 7 and an = 4, then a is equal to A) 6 B) 7 C) 20 D) …

WebClick here👆to get an answer to your question ️ In an A.P 1^st term is 1 and the last term is 20 . The sum of all terms is = 399 then n = .... Solve Study Textbooks Guides. Join / Login >> Class 10 >> Maths >> Arithmetic Progressions >> Sum of an AP >> In an A.P 1^st term is 1 and the last te. Question . In an A.P 1 s t term is 1 and the ... WebLas protecciones eléctricas tienen un papel relevante en la seguridad y en la adecuada operación de un sistema eléctrico de potencia. Particularmente, en el caso de la generación y el trasporte, por su importancia requieren un eficiente sistema de protecciones que permita garantizar la integridad de sus elementos y la continuidad del servicio eléctrico.

WebMar 11, 2024 · answered In an Ap, a=1, an=20, sn=399 then find n Advertisement Answer 3 people found it helpful pragyanrana31 Answer: Sn=n/2 (a+l) . . 399=n/2 (1+20) . . 399*2/21=n . . 19*2=n . . N=38 . . Hope this helps you . . Pls mark Brainliest answer! ️ Find Math textbook solutions? Class 6 Class 5 Class 4 Class 3 Class 2 Class 1 NCERT Class 9 …

WebBesides giving the explanation of In an A.P. if a=1,An=20 and Sn=399, then find the value of n.?, a detailed solution for In an A.P. if a=1,An=20 and Sn=399, then find the value of n.? … little buddy lighterWebIn an A.P. 1st Term is 1 and the Last Term is 20. the Sum of All Terms is = 399 Then N = .... 0 Maharashtra State Board SSC (Marathi Semi-English) 10th Standard [इयत्ता १० वी] little buddy heater safe indoorsWebTo find : n and 20th term from the end We have, l = a + (n – 1)d ⇒ 399 = 3 + (n – 1) × 4 ⇒ 399 – 3 = 4n – 4 ⇒ 396 + 4 = 4n ⇒ 400 = 4n ⇒ n = 100 So, there are 100 terms in the given AP Last term = 100th Second Last term = 100 – 1 = 99th Third last term = 100 – 2 = 98th And so, on 20th term from the end = 100 – 19 = 81st term little buddy heater fuelWebIn an AP if a = 1, a n = 20 and S n = 399, then n is 38. Explanation: ∵ `S_n = n/2 [2a + (n - 1)d]` 339 = `n/2 [2 xx 1 + (n - 1)d]` 798 = `2n + n(n - 1)d` .....(i) And `a_n` = 20. ⇒ `a + (n - 1)d` = … little buddy heater schematicWebApr 28, 2024 · Answer: Given a=1,An=20 and Sn= 399 Step-by-step explanation: Sn = n/2 (a +an) n= 38 Hope it's help you please mark me as a brainlest Find Math textbook … little buddy heater saleWebAnswer : Let the required numbers in A.P.are (a - d), a and (a + d). Sum of these numbers = (a - d) + a + (a + d) = 3a Product of these numbers = (a - d)× a × (a + d)=a (a 2 - d 2) But given, sum = 24 and product = 440 ∴ 3a = 24 a = 8 and a (a 2 - d 2) = 8 (64 - d 2) = 440 [ a = 8] Or, 64 - d 2 = 55 Or, d 2 = 64 - 55 => d 2 = 9 => d = ± 3 little buddy heater reviewWeb98 Likes, 0 Comments - АВТОМОБИЛЬ•ВЫКУП•ОБМЕН•ПРОДАЖА (@avtomarket04) on Instagram: "⚡️Datsun Mi-Do⚡️ Год выпуска ... little buddy heater golf cart